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I need someone...to help me with this question! :)3^3 = x + 5^5A. -3098B. 3098C. 3152
4 months ago
Q:
I need someone...to help me with this question! :)3^3 = x + 5^5A. -3098B. 3098C. 3152
Accepted Solution
A:
Β Β Β Β β£ Assignment: [tex]\bold{Solve \ Equation: \ 3^3=x+5^5}[/tex]ββββββββ Β Β Β Β β£ Answer: [tex]\boxed{\bold{x=-3098}}[/tex]ββββββββExplanation: βββββββββββββ Β Β Β Β β€ [ Step One ] Switch Sides[tex]\bold{x+5^5=3^3}[/tex] Β Β Β Β β€ [ Step Two ] Simplify: [tex]\bold{5^5=3125}[/tex][tex]\bold{x+3125=3^3}[/tex] Β Β Β Β β€ [ Step Three ] Simplify: [tex]\bold{3^3=27}[/tex][tex]\bold{x+3125=27}[/tex] Β Β Β Β β€ [ Step Four ] Subtract 3125 From Both Sides[tex]\bold{x+3125-3125=27-3125}[/tex] Β Β Β Β β€ [ Step Five ] Simplify[tex]\bold{x=-3098}[/tex]ββββββββ[tex]\bold{\rightarrow Mordancy \leftarrow}[/tex]